160-2q-6q^2=0

Solution for 160-2q-6q^2=0 equation:

160-2q-6q^2=0

a = -6; b = -2; c = +160;
Δ = b2-4ac
Δ = -22-4·(-6)·160
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-62}{2*-6}=\frac{-60}{-12}
=+5
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+62}{2*-6}=\frac{64}{-12}
=-5+1/3
$